2x^2+6x+13+8x=-1-2x

Solution for 2x^2+6x+13+8x=-1-2x equation:

2x^2+6x+13+8x=-1-2x

We move all terms to the left:

2x^2+6x+13+8x-(-1-2x)=0

We add all the numbers together, and all the variables

2x^2+6x+8x-(-2x-1)+13=0

We add all the numbers together, and all the variables

2x^2+14x-(-2x-1)+13=0

We get rid of parentheses

2x^2+14x+2x+1+13=0

We add all the numbers together, and all the variables

2x^2+16x+14=0

a = 2; b = 16; c = +14;
Δ = b2-4ac
Δ = 162-4·2·14
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-12}{2*2}=\frac{-28}{4}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+12}{2*2}=\frac{-4}{4}
=-1
$